import Foundation
// Assuming you have a URI or a URL to the file val uri = Uri.parse("https://example.com/path/to/hbuz44wwr60l.mp4") val intent = Intent(Intent.ACTION_DOWNLOAD_COMPLETE) intent.data = uri // More setup as required On iOS, you might use URLSession or a third-party library to download a file:
if __name__ == '__main__': app.run(debug=True) In a Node.js environment with Express, you could achieve this as follows: Download File hbuz44wwr60l.mp4
import android.content.Intent import android.net.Uri
app.get('/download/:filename', (req, res) => { const filename = req.params.filename; const file = path.join(filePath, filename); fs.stat(file, (err, stats) => { if (err) { console.error(err); res.status(404).send('Not found'); } else { res.download(file, filename, (err) => { if (err) { console.error(err); } }); } }); }); import Foundation // Assuming you have a URI
const express = require('express'); const app = express(); const fs = require('fs'); const path = require('path');
app = Flask(__name__) file_path = '/path/to/your/files/' # Ensure this is a server-safe path { const filename = req.params.filename
from flask import Flask, send_from_directory